# An lnvestigator interviewed `100` students to determine the performance of three drinks milk, coffee and tea. The investigator reported that `10` students take all three drinks, 20 students take milk and coffee, `30` students take coffee and tea, `25` students take milk and tea, `12` studnts take milk only. `5` students take coffee only and `8` student take tea only. Then the number of students who did not take any of the three drinks is `lambda` . The value of `(lambda)/(4)` is equal to

Updated On: 16-5-2021

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An investigator…………. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_P06_17_MPCT_P7_XI_E01_065_S01.png" width="80%">

Transcript

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00:00 - 00:59 | investigator interviewed 100 students to determine the performance of three drinks milk coffee and tea reported that 10 students take all three drawings 20 students take milk and coffee 36th and stay coffee and tea and 25 students take milk Candy students take milk only five students take coffee onley and eight students take the only the number of students who did not take any of the three Rings is land of the value of Land by 4 is equal to sunao in this question is just have to calculate the number of students who did not take any of these three rings and then we are divided by 4 will solve this question with the help of Venn diagram will solve this question with the help of Venn diagram of all girls girls is will be for milk |

01:00 - 01:59 | dasvin bi coffee coffee and the third one will be 43rd one will be cause this will be for tea now this is for milk this is for coffee and this will be for now according to the question write down five student 12th students take milk only so you know that these things this is the region in which milk and coffee interested in this is the region in which milk and intersect and this is the region where coffee and intersect and this middle region is |

02:00 - 02:59 | which is common between all of three now now 12 students take milk only take milk only so it will be here and five students take coffee on least it will be here and a student take only t-shirt will be here now let the third line that is 10 students take all the three rings all the three is taken by 10 students so this region which is taken by all of The Three Students it will be 10 now we know that 27 take milk and coffee now milk and coffee is taken by 20 students but in which 10 students are already a student which also took milk and coffee 28 will be 10 now |

03:00 - 03:59 | 30 student coffee and tea coffee and tea is taken by 30 students but we already excluded the 10 which to coffee and tea and also milk 30 mast and it will be 2020 for students take milk anti 25 students make it in which we have to do it already 10 Rs 200 which took milk and tea and also copy 25 and it will be 15 so now the table is the wind diagram is complete and just be hard to find it hard to find how many students who did not take any of the three doing now you know that the sum of the minus the sum of subtracted from hundred will be the students who did not take anything so students |

04:00 - 04:59 | who did not take energy drinks is equal to now 100 - some of the 12 + 8 + 5 + 15 + 10 + 10 + 2300 - 12 12 + 17 + 25 + 15 15 X 40 50 60 80 will be a T20 now cylinder is equal to 20 because the value of land was the value of land was that number of students who did not take any of the three days sunao Lambda by 4 is equal to 4 is equal to 24 that is 5414 Kaise answer will be answer will be option for |

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View AllVery Important Questions

X(वास्तविक या सम्मिश्र) के मानों की संख्या जो समीकरण निकाय

1+z+z^(2)+z^(3)+……….+z^(17)=0

तथा

1+z+z^(2)+z^(3)+…………+z^(13)=0

को एक साथ संतुष्ट करते है होगी:

यदि

|z_(1)|=1,|z_(2)|=2,|z_(3)|=3

तथा

|9z_(1)z_(2)+4z_(1)z_(3)+z_(2)z_(3)|=12

हो तो

|z_(1)+z_(2)+z_(3)|

बराबर है

बिंदु z वक्र

|z-4-3i|=2

पर आर्गण्ड तल में गति करता है।

|z|

का अधिकतम तथा न्यूनतम मान है

सम्मिश्र तल पर बिंदुओं का समुच्चय इस प्रकार है कि

z^(2)+z+1

का मान वास्तविक तथा धनात्मक है। (जहां

z=x+iy,x,y inR

) तो समुच्चय है

यदि

i=sqrt(-1)

हो तो

4+5(-1/2-(isqrt(3))/2)^(334)+3(-1/2+(isqrt(3))/2)^(365)

का मान है

|z|le4

तथा

Argz=(pi)/3

दोनों को आर्गण्ड तल पर संतुष्ट करने वालेा बिंदुओं का समुच्चय है

यदि

Arg(z-2-3i)=(pi)/4

हो तो z का बिंदु पथ है

मूल बिंदु तथा समीकरण

z^(2)+pz+q=0

के मूल समबाहू त्रिभुज बनाते हैं यदि

बिंदु

z_(1)

तथा

z_(2)

सम अष्टबहुभुज के आसन्न शीर्ष है। शीर्ष

z_(3)

जो कि

z_(2),(z_(3)!=z_(1))

के आसन्न है को निम्न से दर्शाया जायेगा

दो सम्मिश्र संख्याओं

z_(1)

तथा

z_(2)

के लिए

(az_(1)=b barz_(1))(cz_(2)+dbarz_(2))=(cz_(1)+dbarz_(1))(az_(2)+b barz_(2))

होगा यदि

(a,b,c,d epsilon R)

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